How to remove all characters before last matching character in Lua

Question

So i'm a little bit confused about Lua pattern matching. I have a script to log history of videos played with MPV, but i don't need full path there, just filename is enough, so i wanted to remove all everything before last / char. In Python i would do simple

filename = re.sub(r'.*/', '', path)

But i failed horribly using Lua pattern matching. How does one do that?

Example input with desirable output:

>>> path = "/some/path/to/file.mkv"
>>> filename = re.sub(r'.*/', '', path)
>>> filename
'file.mkv'

Answer 1

Seems i have figured it out by myself, oh well. Used this kind of pattern:

path = "/path/to/some/file"
filename = path:gsub(".*/", "")

filename now contains only "file".

EDIT: As suggested, i changed path:gsub("(.*).*/",'') to path:gsub(".*/", "") instead since it's much more readable syntax .