How to write an XPath using AND Operator to add multiple spans in a single XPath?

Question

The page contains a Product name-(3 OF 3) GOLDEN GLOW ( DELUXE ). The product name has 6 different spans so we want to print the product name "GOLDEN GLOW ( DELUXE )", ie including the all the spans so I have tried to use the and multiple time inside the [] but it didn't work. Below is the XPath:

//*[@class='itemTitleCopy no-mobile' and contains(@class, 'no-mobile') and contains(@class, 'sizeDescriptionTitle no-mobile') contains(@class, 'no-mobile') ]

Below is the HTML code:

<span class="m-shopping-cart-item-header-number">
   ( 
   <span id="itemNo-1" class="itemNo">3</span>
   of 
   <span id="totalItems-1" class="totalItems">3</span>
   )
   <span class="itemTitleCopy no-mobile" id="itemTitleCopy-1">Golden Glow</span>
   <span class="no-mobile">(</span>
   <span class="sizeDescriptionTitle no-mobile" id="sizeDescriptionTitle-1">Deluxe</span>
   <span class="no-mobile">)</span>
</span>

---

Update

Code trials:

WebElement checkoutShippingProdName = new WebDriverWait(getDriver(), 20).until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//span[@class='m-shopping-cart-item-header-number']"))); 
String shipProdElementHtml = checkoutShippingProdName.getAttribute("innerHTML"); 
String[] shipProdElementHtmlHtmlSplit = shipProdElementHtml.split("span>"); 
String currentProd = shipProdElementHtmlHtmlSplit[shipProdElementHtmlHtmlSplit.length -1]; 
currentProd = StringEscapeUtils.unescapeHtml4(StringUtils.trim(currentProd)); 
System.out.println("The Product Name is:" + currentProd);

Answer 1

'//span[@class="totalItems"]/following-sibling::span'

should select all span nodes after span with class="totalItems" . There might be different approaches of extracting required text content depends on Selenium binding.

This is Python code to get required output:

text = " ".join([span.text for span in driver.find_elements_by_xpath('//span[@class="totalItems"]/following-sibling::span')])
print(text)
#  'Golden Glow(Deluxe)'

Answer 2

As @Michael Kay has answered what you need is to use to or operator!

You can do this with the findElements Selenium.

It should look something like this:

driver.findElements(By.xpath("//*[@class='itemTitleCopy no-mobile' or contains(@class, 'no-mobile') or contains(@class, 'sizeDescriptionTitle no-mobile')]"))

This returns a list of WebElements now you can iterate through them and join the text to create your desired string of "GOLDEN GLOW ( DELUXE )" .

All the credit is to @Michael Kay I just gave you the example...

Answer 3

You seem to be confused about the meaning of and and or . The and operator within a predicate means that both conditions must be true: it's more restrictive, so in general less data will be selected. The or operator means either condition must be true: it's more liberal, so more data will be selected.

You seem to be thinking of "and" as meaning "union" - select X and (also select) Y. That's never its meaning in boolean logic.

Answer 4

Use this:

//*[@class=('itemTitleCopy no-mobile','sizeDescriptionTitle no-mobile','no-mobile')]

Hope it will solve.

Answer 5

To extract the text Golden Glow ( Deluxe ) you can use the following Locator Strategy :

• Using XPath :

   String myString = driver.findElement(By.xpath("//span[@class='m-shopping-cart-item-header-number']")).getText(); String[] parts = myString.split("?<=)"); System.out.println(parts[1]);