I need to sum and group consecutive integers by spoken_correctly
> 0.
I'm able to find out which sections are consecutive by looking at lag
and lead
, but then am not sure how to sum contiguous groups consecutive
field's values.
Ie, I have two groups where there are consecutive spoken_correctly
values > 0. The first group in green has three rows of non-zero spoken_correctly
, the second group in green has two.
Desired output:
This SQL produces the first image above output:
select *, case when (q.times_spoken_correctly > 0 and (q.lag > 0 or q.lead > 0)) then 1 else 0 end as consecutive
from (
select *, lag(q.times_spoken_correctly) over (partition by q.profile_id order by q.profile_id) as lag, lead(q.times_spoken_correctly) over (partition by q.profile_id order by q.profile_id) as lead
from (
SELECT *
FROM ( VALUES (3, 0, '2019-01-15 19:15:06'),
(3, 0, '2019-01-15 19:15:07'),
(3, 1, '2019-01-15 19:16:06'),
(3, 2, '2019-01-15 19:16:10'),
(3, 2, '2019-01-15 19:17:06'),
(3, 0, '2019-01-15 19:17:11'),
(3, 0, '2019-01-15 19:39:06'),
(3, 3, '2019-01-15 19:40:10'),
(3, 4, '2019-01-15 19:40:45')
) AS baz ("profile_id", "times_spoken_correctly", "w_created_at")
) as q
) as q
This is a gaps and islands problem, which can be solved by forming groups of sequences using row_number
select profile_id, count(*) as consec FROM
(
SELECT t.*, row_number() OVER ( PARTITION BY profile_id ORDER BY w_created_at ) -
row_number() OVER ( PARTITION BY profile_id, CASE times_spoken_correctly
WHEN 0 THEN 0 ELSE 1 END
ORDER BY w_created_at ) as seq --group zeros and non zeros
FROM t ORDER BY w_created_at
) s WHERE times_spoken_correctly > 0 --to count only "> zero" groups.
GROUP BY profile_id,seq;
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