whenever I run this code, if I type a string as my input, I get an error on line 11. Help? I am not sure how to run an else statement or something asking what if they put a string rather than an integer (choice variable). I am new, so much help would be appreciated!
Here is my code:
import java.util.Scanner;
public class rockPaper {
public static void main(String args[]) {
System.out.println("Hello world");
int rock = 0;
int paper = 1;
int scissors = 2;
Scanner input = new Scanner(System.in);
System.out.println("Rock, Paper, or Scissors(0, 1, or 2)? Enter your integer: ");
int choice = input.nextInt();
int aIChoice = (int) (Math.random() * 3);
if (choice == rock) {
switch (aIChoice) {
case 0:
System.out.println("AI chose rock.");
System.out.println("Rock ties with rock!");
break;
case 1:
System.out.println("AI chose paper.");
System.out.println("Fail. Paper trumps rock.");
break;
case 2:
System.out.println("AI chose scissors.");
System.out.println("You win! Rock trumps scissors.");
break;
default:
break;
}
} else if (choice == paper) {
switch (aIChoice) {
case 0:
System.out.println("AI chose rock.");
System.out.println("You win! Paper trumps rock.");
break;
case 1:
System.out.println("AI chose paper.");
System.out.println("Paper ties with paper!");
break;
case 2:
System.out.println("AI chose scissors.");
System.out.println("Fail. Scissors trumps paper.");
break;
default:
break;
}
} else if (choice == scissors) {
switch (aIChoice) {
case 0:
System.out.println("AI chose rock.");
System.out.println("Fail. Rock trumps scissors.");
break;
case 1:
System.out.println("AI chose paper.");
System.out.println("You win! Scissors trumps paper.");
break;
case 2:
System.out.println("AI chose scissors.");
System.out.println("Scissors ties with scissors!");
break;
default:
break;
}
} else {
System.out.println("Nope!");
}
input.close();
}
}
As stated above, if I run the code, and I type in any letters(a string), I get an error referencing to line number eleven. I am not sure what I should do, because obviously as I've mentioned adding an else statement to all of this does not ensure the "nope" if they entered a string.
Usually you would not accept a string input. If you really need to for some reason, you could replace the input line with String choice = input.next()
then do whatever tests you need to with it. After you confirm it's the input you want refer to this post to convert from a String to int.
Not quite sure what do you expect in case user provides invalid input, but, I think, reasonable option would be to check the input and print error message to the user if input is not a valid integer. For this just add this code below instead of this line in your code: int choice = input.nextInt();
int choice = -1;
if (input.hasNextInt()) {
choice = input.nextInt();
} else {
System.out.println("Please provide valid integer input: Rock, Paper, or Scissors(0, 1, or 2)?");
}
PS Also it would be good to check if your integer is in range [0,2].
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