How to print the first elements of an array according to an int?

Question

I have an array of chars, I need to print in the console its first chars according to an int, so if the int is equal to 3, it should print args[0], args[1], args[2]. If the int is 7 it should print the first seven args.

Scanner scanner = new Scanner(System. in);
    char[] arguments = scanner.nextLine().toCharArray();
    scanner.close();

    int i1 = 0;

    while (i1 <= arguments.length) {        

        System.out.println("???");
        i1 = i1++;

    }

The int can be every number, so I can't just do a switch statement because it would be too long. And the elements must be in the same line. Input should be like "ABCDEF"/"ABC".

Answer 1

public static void main(String[] args) {
        Scanner scanner = new Scanner(System. in);
        // array of characters given by user
        char[] arguments = scanner.nextLine().toCharArray();
        // the value of int given by user i.e how many characters need to print
        int intNumber = scanner.nextInt();
        // closing the connection for scanner
        scanner.close();
        //for loop that execute till the given value of int
        for(int i=0; i<intNumber; i++) {
            //condition check to avoid ArrayIndexOutOfBoundsException
            if(i < arguments.length)
            // For printing characters in single line
            System.out.print(arguments[i]);
        }

Answer 2

//Index provided by user
int index = input.nextInt();

//For loop which iterates over the array from the beginning to the input index
for (int currentIndex = 0; currentIndex < index; currentIndex++) {
    //Printing the current array character
    System.out.print(arr[currentIndex]);
}
//Printing line when loop has finished traversing
System.out.println();

Answer 3

IntStream.range(0, num).forEach(x -> System.out.print(charArray[x]));

如果您更喜欢Java8，则此代码段将帮助您解决该问题。

Answer 4

If you don't want top use Streams, why not:

String s = scanner.nextLine();
int end = Math.min(n,s.length());
System.out.println( s.substring(0,end) );

where n is the number of characters?