Remove items from specific positions on recyclerView

Question

I have a recyclerView and a List<> which contains some random position

All i want to do is remove recyclerView item from position stored in the list.

Answer 1

更好的方法是从Adapter中删除对象，然后调用notifyDatasetChanged 。

Answer 2

from your activity you can loop your list of item position you want to delete

for(int i = 0; i< listitem.size(); i++){adapter.deleteItem(position);}

then in your adapter implement removeItem function:

public void deleteItem(int index) {
    Dataset.remove(index);
    notifyItemRemoved(index);
}

Answer 3

You can remove a single item in RecyclerView adapter with:

List<YourData> list;

// position of your data in the list.
private removeItem(int position) {
  list.remove(position);
  notifyItemRemoved(position);
}

But you can't use it if you need to remove multiple items sequentially. The following won't work:

removeItem(3);
removeItem(36);
removeItem(54);

because the list index has been changed after the first call of removeItem() .

So, you need to depend on an Id for your data. For example, with the following User class:

public class User {
  private long id;
  private String name;

  // constructor
  // setter
  // getter

}

you can remove multiple items sequentially by checking the id with the following method:

// list of your User
List<User> users;

// id is your User id
private removeItem(int id) {
  for(int i = 0; i < users.size(); i++) {
    User user = users.get(i)
    if(user.getId() == id) {
      users.remove(i);
      break;
    }
  }
}

which can be used if you know the id:

removeItem(3);
removeItem(36);
removeItem(54);

Of course, you can add another method to remove items by using a list of id:

private removeItems(List<Integer> ids) {
  for(Integer id: ids) {
    removeItem(id);
  }
}