I have run a python script that created multiple variables. Now I want to iterate over a few dataframes (created by the script) matching a specific pattern and perform simple operations on them. Initially I want to get the number of rows (with shape()
) of each of the dataframes in list_dfs
, as shown below:
['FAILEDRuns_0112',
'FAILEDRuns_0121',
'FAILEDRuns_0126',
'FAILEDRuns_0129',
'FAILEDRuns_0131',
'FAILEDRuns_0134',
'FAILEDRuns_0135',
'FAILEDRuns_0137',
'FAILEDRuns_0142',
'FAILEDRuns_0153',
'FAILEDRuns_0165',
'FAILEDRuns_0171',
'FAILEDRuns_0175']
In fact if I do:
for i in list(filter(failed_runs_finder.findall, dir())):
print(locals()[i].shape[0])
I get the number of rows printed onto the screen:
1
0
0
0
1
0
0
0
0
0
0
0
0
Which contains the information that I need, though not in the format that I want. Eventually what I need to know is the number of 1's and the number of zero's, so I thought about getting a list comprehension, to eventually compare the total sum (ie the number of 1's) with the length of the list ie the total number of elements.
However, if I do:
[locals()[i].shape[0] for i in list_dfs]
I get the following error:
KeyError: 'FAILEDRuns_0112'
I don't quite understand where the error is coming from. As far as I see, it is not in terms of syntax of list comprehensions.
Does it have anything to do with using locals()
within a list comprehension?
My second option would be to build a df iteratively and get the sum, though I think it is simpler with list comprehension and I don't quite get where the error is coming from.
Try this instead if you really must rely on locals()
:
[v.shape[0] for k, v in locals().items() if k in list_dfs]
However it would probably be a better approach, as suggested, to use a single dict
to store all the names and DataFrame
objects instead.
If you want to get the counts of rows:
from collections import Counter
cnt = Counter(v.shape[0] for k, v in locals().items() if k in list_dfs)
cnt[1]
# 2
cnt[0]
# 11
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