INPUT:
empid department names salary
----------------------------------
1 dotnet klrahul 1000
2 dotnet dhawan 2000
3 dotnet virat 1500
4 design dhoni 3000
5 design karthik 2000
6 design phant 3040
7 php chawal 4000
8 php kpandya 2000
9 php skaual 4300
10 php bhumra 2000
11 dotnet vijay 1646
OUTPUT:
empid department names salary
----------------------------------
1 dotnet klrahul 1000
2 dotnet dhawan 2000
3 dotnet virat 1500
11 dotnet vijay 1646
7 php chawal 4000
8 php kpandya 2000
9 php skaual 4300
10 php bhumra 2000
You can use a window function :
select top (1) with ties t.*
from (select t.*, count(*) over (partition by dept) as cnt
from table t
) t
order by rank() over (order by cnt desc), dept;
please try this code
SELECT emp_id, dept,count(*) OVER (PARTITION by dept)
FROM table
ORDER BY count(*) OVER (PARTITION by dept) desc,
emp_id
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