column name | datatype
order_date | timestamp w/ timezone (Eg: '2019-01-20 23:59:10+08')
looking to convert the timestamp to day of the week example: 2019-01-20 = 'Sunday'
You can use EXTRACT to extract the day of week as an integer and then convert it to a string:
SELECT
CASE EXTRACT(DOW FROM order_date AT TIME ZONE 'UTC')
WHEN 0 THEN 'Sunday'
WHEN 1 THEN 'Monday'
...
END
FROM test
You can use the following function which will return the day of week of a given date
create function day_of_week(@d as date) returns varchar(20)
as
begin
declare @day_of_week as varchar(20)
select @day_of_week =case datepart(w,getdate())
when 1 then 'Sunday'
when 2 then 'Monday'
when 3 then 'Tuesady'
when 4 then 'Wednasday'
when 5 then 'Thursday'
when 6 then 'Friday'
when 7 then 'Saturday'
end
return @day_of_week
end
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