I have a model I am trying to connect to in R. I open the model by running;
> library(plumber)
> r <- plumb("deploy_ml_credit_model.R")
Warning message:
In readLines(file) :
incomplete final line found on 'deploy_ml_credit_model.R'
> r$run(swagger = FALSE)
Starting server to listen on port 3582
I then head over to Python and run the following;
Python Code:
import requests
import json
response = requests.post(
“http://127.0.0.1:3582”
, headers={“Content-Type”: “application/json”}
, data=json.dumps({
"Status.of.existing.checking.account": "A11"
, "Duration.in.month": 24
, "Credit.history": "A32"
, "Savings.account.bonds": "A63"
})
)
print response.json()
Where I obtain the following error:
File "<ipython-input-41-507692393845>", line 4
“http://127.0.0.1:3582”
^
SyntaxError: invalid character in identifier
I open the link in the browser and I obtain this message: {"error":["404 - Resource Not Found"]}
Where am I going wrong with this? I have plumber
running in the background in RStudio so it should connect. Do I have some issues regarding permissions or firewall issues?
EDIT:
I am still obtaining the following message when I type http://127.0.0.1:3582/predict
- the error http://127.0.0.1:3582/predict
. I clean up the code and I get the following error:
Code 2:
import requests
import json
response = requests.post(
"http://127.0.0.1:3582"
, headers={"Content-Type": "application/json"}
, data=json.dumps({
"Status.of.existing.checking.account": "A11"
, "Duration.in.month": 24
, "Credit.history": "A32"
, "Savings.account.bonds": "A63"
})
)
print response.json()
Error 2:
File "<ipython-input-49-0669c2ac9d9d>", line 15
print response.json()
^
SyntaxError: invalid syntax
EDIT 3:
I type:
print (response)
and I obtain this error:
<Response [404]>
But the R model is running in the background
EDIT:
Using:
curl -X POST "http://127.0.0.1:8000/__swagger__/predict" -d '{"Status.of.existing.checking.account": "A11", "Duration.in.month": 24, "Credit.history": "A32", "Savings.account.bonds": "A63"}' -H "accept: application/json"
Gives this error:
curl -X POST "http://127.0.0.1:8000/__swagger__/predic
t" -d '{"Status.of.existing.checking.account": "A11", "Duration.in.month": 24, "Credit.history":
"A32", "Savings.account.bonds": "A63"}' -H "accept: application/json"
<h1>Bad Request</h1>curl: (6) Could not resolve host: A11,
curl: (6) Could not resolve host: Duration.in.month
curl: (6) Could not resolve host: 24,
curl: (6) Could not resolve host: Credit.history
curl: (6) Could not resolve host: A32,
curl: (6) Could not resolve host: Savings.account.bonds
curl: (3) [globbing] unmatched close brace/bracket in column 4
EDIT:
I run this line:
curl POST -H 'Content-Type:accept:application/json' -d "{/"Credit.history/":/"A32/"}" http://127.0.0.1:8000/__swagger__/predict
So I decided to remove a lot of what I want to send to the model down to just one variable and now I am getting this error:
curl POST -H 'Content-Type:accept:application/json' -d "{/"Credit.history/":/"A32/"}" http://127.0.0.1:8000/__swagger__/predict
curl: (6) Could not resolve host: POST
{"error":["500 - Internal server error"],"message":["Error: lexical error: invalid char in json text.\n {/Credit.history/:/A32/}\n
(right here) ------^\n\n"]}
You have very weird quotes in the string
“http://127.0.0.1:3582”
– they should just be straight quotes:
"http://127.0.0.1:3582"
Your "Error 2" seems to refer to using Python 3 with Python 2 syntax. print
is a regular function in Py3, so you need to use parentheses around it:
import requests
import json
response = requests.post(
"http://127.0.0.1:3582",
headers={"Content-Type": "application/json"},
data=json.dumps(
{
"Status.of.existing.checking.account": "A11",
"Duration.in.month": 24,
"Credit.history": "A32",
"Savings.account.bonds": "A63",
}
),
)
print(response.json())
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