I have a regex: r'((\\+91|0)?\\s?\\d{10})'
I'm trying to match numbers like +91 1234567890
, 1234567790
, 01234567890
.
These numbers shouldn't be matched: 1234568901112
because it doesn't start with +91 or 0 or doesn't have just 10 numbers:
When I try to use re.findall()
:
re.findall(r'((\+91|0)?\s?\d{10})', '+91 1234567890, 1234567790, 01234567890, 1234568901112')
[('+91 1234567890', '+91'),
(' 1234567790', ''),
(' 0123456789', ''),
(' 1234568901', '')]
You can notice that in the third and fourth index the output is not what I want. My expected output at third index is 01234568890 and because it starts with 0 and followed by 10 characters. But it's only showing the first 10 characters. Also I don't want the output in the 4th index because it the number doesn't completely match. So either it matched the complete word/string else it is invalid.
Is there any other regex that I can use? Or a function? What am I doing wrong here?
The expected output is:
[('+91 1234567890','1234567790', '01234567890']
Please let me know if any more clarifications are needed.
You may use
r'(?<!\w)(?:(?:\+91|0)\s?)?\d{10}\b'
See the regex demo .
The point is to match these patterns as whole words, the problem is that the first part is optional and one of the optional alteratives starts with a non-word char, so a single \\b
word boundary won't work here.
Details
(?<!\\w)
- there should be no word char immediately to the left of the current location (?:(?:\\+91|0)\\s?)?
- an optional occurrence of
(?:\\+91|0)
- +91
or 0
\\s?
- an optional whitespace \\d{10}\\b
- ten digits matches as a whole word, no word chars allowed on both sides import re
s = '+91 1234567890, 1234567790, 012345678900, 1234568901112, 01234567890'
print(re.findall(r'(?<!\w)(?:(?:\+91|0)\s?)?\d{10}\b', s))
# => ['+91 1234567890', '1234567790', '01234567890']
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