regex replace whole string with http with blank

Question

lets say I have a string

string = "Today is going well the dog jumped over the fence. The fence was 
my neighbors asdkhttps://www.urldefence.org/ult/sdfo/90nf3f/lknfksjdn? 
>>>09sdkfjnkbIAS(F89kjfs and here are some more words before another link 
lkm.http//www.someothersite.com/kasd09/3oif/3fo3/3/nffiosuf??? 
DF*SDF***8skdjnf and some more words in the end."

I want to just replace the long strings that contain the http link, defined by space before the text, and space after, with http being somewhere in the middle.

I've been trying..

re.sub('\bhttps?\b', '', string)
re.sub('https?.*?', '', string)
re.sub('https?.*?([\s+])', '', string)

having trouble connecting the dots.

Answer 1

I am not much good in regex but I tried following regex and it match the string you want with space. So you can try this if work.

http.*?([\s])