Identify the tuple in the list of tuples if the tuple contains substring

Question

I have a list

l1 = [('is', 'VBZ'), ('plant', 'NN')]

I want to check if the VB in present in the list

I have used the following code but it is not giving me the result.

match = [x for x in l1 if 'VB' in x]

Answer 1

I think you need:

l1 = [('is', 'VBZ'), ('plant', 'NN')]

print([x for x in l1 if 'VB' in x[1]])

Output

[('is', 'VBZ')]

Why your code is not working

You are checking if VB is in ('is', 'VBZ') and it is not. As I understand those are POS tags and will always be at 1st index. You need to check if VB is present at index 1 of each tuple in the list

Answer 2

In case you do not have 'VB' occurring always on 1st index,

match = [y for y in l1 if any(['VB' in x for x in y])]

step 1 : Visit a tuple one by one.

step 2 : Check if string 'VB' exists in any of the string-items of the visited tuple.

Answer 3

In your solution you want to check for substring, for that you will need to search through the elements in Tuple .

If you want to search exact string then your solution is right

'VBZ' in ('is', 'VBZ')
==> True

'VB' in ('is', 'VBZ')
==> False

if you know exatly 2 elements will be in tuple

[tu for tu in l1 if 'VB' in (tu[1] or tu[0])] 

==> [('is', 'VBZ')]

if you are not sure of the elements in tuple

[tu for tu in l1 if any(['VB' in elem for elem in tu])] 
==> [('is', 'VBZ')]