I am trying to use Python to open another file. This file is going to start up a socket and create threads for listening for additional connections, and threads for sending/receiving data. The main thread will not return.
However, if the setup of sockets fail, I want to return a error code to the other python script that executed the subprocess.
main.py
py3output = subprocess.check_output(['python3', 'py3.py'])
print('py3 said:' + str(py3output))
py3.py
def returnme():
return 10
returnme()
When I run this, it prints:
py3 said:b''
I am just trying to figure out how to get the return value back to the main calling program.
To return an exit code n
back to the OS, you need sys.exit(n)
. But seems like you do not want to check the exit code but the stdout otput. So your program might need to rewrite to:
def returnme():
return 10
print(returnme())
You should only return a string as a standard output using following code:
sample.py
import sys
def returnme():
sys.stdout.write(str(10))
sys.stdout.flush()
returnme()
main.py
from subprocess import check_output
output = check_output(['python','sample.py'])
print('Sample.py says :' + output)
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