I am a beginner coder. My code supposes that the user will enter a word with '*'(stars) and display "same" if the chars before and after the * are the same. For example, for the input ja'*'aisfun, my output should be "same" because a * is between to identical letters. My code seems to work for most cases such as several stars, however when I try a user input like "ja' 'a' 'isfun", the output is "same" even though it should display "different" because of 'a' and 'i' being different letters. I suppose my code is capable of checking only the first star in this case. How can I fix this problem? (Consider the stars wihout the apostrophes)
String ind = "DIFFERENT";
for (int i = 0; i< s.length(); i++) {
if ((s.charAt(i) == '*') && (s.charAt(i-1)) == s.charAt(i+1))
ind = "SAME";
}
System.out.print(ind);
}
System.out.print("NO");
You must limit the loop from the 2nd char up until the 2nd from the end and break when a match is found (I suppose):
String ind = "DIFFERENT";
for (int i = 1; i < s.length() - 1; i++) {
if ((s.charAt(i) == '*') && (s.charAt(i-1)) == s.charAt(i+1)) {
ind = "SAME";
break;
}
}
System.out.print(ind);
Also drop:
System.out.print("NO");
First, you need to fix your loop index. It should go from 1
to s.length() - 1
, otherwise you would get a index out of bounds exception if the last or first char is a *
.
Secondly, it seems like you want to output "DIFFERENT" if there is at least 1 pair of characters around a *
that is different. You can do this by break
ing out of the loop as soon as you find a pair that's different:
// be careful of bounds of the indexes
for (int i = 1; i< s.length() - 1; i++) {
if ((s.charAt(i) == '*')) {
if ((s.charAt(i-1)) == s.charAt(i+1)) {
ind = "SAME";
} else {
ind = "DIFFERENT";
break;
}
}
}
System.out.print(ind);
Alternatively, you could use a regex solution:
if (Pattern.compile("(.)\\*(?!\\1)").matcher(s).find()) {
System.out.println("DIFFERENT");
} else {
System.out.println("SAME");
}
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