Model.where() with multiple params with check if they are present in rails

Question

I am new to Rails. I started working on a POC.

My controller code is below:

  @xyz = if params[:id].present?
           if params[:mobile_number].present?
             Seeker.where("id = ? and mobile_number = ?" , params[:id], params[:mobile_number])                    
           else                    
             Seeker.where("id = ?", params[:id])
           end
         elsif params[:seekerid].present?
           Seeker.where("mobile_number = ?" , params[:mobile_number])
         else
           Seeker.where(nil);
         end

But I don't think it's a good approach. Consider if I have many parameter then putting present? condition then forming query would become complex. Or can I form a query separately then place it into where condition as instance variable.

What is the best approach?

Answer 1

You could add where statements incrementally when each parameter is present:

@xyz = Seeker.scoped
@xyz = @xyz.where(id: params[:id]) if params[:id].present?
@xyz = @zyx.where(mobile_number: params[:mobile_number]) if params[:mobile_number].present?

A cleaner approach could be to move that logic to some scope or class method in the Seeker model maybe.

Answer 2

Hi I am new to Rails

If you are using searching for small project, small database, you can use Ruby's scope , and take a look at arieljuod's answer. But if you want to make your searching feature is faster, deeper, ... you can find some gems:

• Sunspot
• Searchkick
• Searchlogic
• Ransack

And there are many other amazing ways with Ruby on Rails.

Happy coding!!!

Answer 3

If you want to find record based on each parameter are coming and have value that best way to use this is

params = {id: nil, mobile_number: "98XXXXXX12" }
Seeker.where(params.compact)

compact will remove nil value from params and directly find with Existing parameter.

NOTE: It will remove only nil value not " " blank String