How to check if a string contains a substring from an array and split it

Question

I have an array of string like:

var matchCodFisc = ["C.F.", "CF", "Cod.Fisc.", "C.F"]

and I want to check if in my string (eg var myString= "Cod.Fisc.FGDTFR34L16G643W" ) exists that substring (in this case "Cod.Fisc"). If I found the substring I want to split my string in two parts like ["Cod.Fisc", "FGDTFR34L16G643W"] . How can I do that using JavaScript?

Answer 1

You could find the string and take the rest. Maybe it is better to sort the pattern array by length descending, because it finds the longest string first.

 var matchCodFisc = ["CF", "CF", "Cod.Fisc.", "CF"], string = "Cod.Fisc.FGDTFR34L16G643W", found = matchCodFisc .sort((a, b) => b.length - a.length) .find(s => string.startsWith(s)), result = [found, string.slice(found.length)]; console.log(result); 

Answer 2

You can use find, includes and split

• First find the matching value from matchChodFisc using find and includes
• Create a regex pattern based on value of found
• Split using regex we built and fillter empty values

 var matchCodFisc = ["CF", "CF", "Cod.Fisc.", "CF"] var myString= "Cod.Fisc.FGDTFR34L16G643W" let found = matchCodFisc.find(val=> myString.includes(val)) let regex = new RegExp(`(${found})`, 'gi') let splited = myString.split(regex).filter(Boolean) console.log(splited) 

Answer 3

You could do with Array#findIndex method using Str.includes()

 var matchCodFisc = ["CF", "CF", "Cod.Fisc.", "CF"] var myString = "Cod.Fisc.FGDTFR34L16G643W"; var resindex = matchCodFisc.findIndex(a => myString.includes(a)); console.log([ matchCodFisc[resindex], myString.split(matchCodFisc[resindex])[1] ]) 

Answer 4

Make your array into a regular expression:

 const matchCodFisc = ["CF", "CF", "Cod.Fisc.", "CF"]; const myString = "Cod.Fisc.FGDTFR34L16G643W"; const splitRegex = new RegExp('('+matchCodFisc.join('|')+')\\\\w+', 'g'); console.log(splitRegex); let result = splitRegex.exec(myString) console.log(result[1])