copy element of first array to second array with pointer

Question

i want to copy element of first array to the second array with pointer but after compiling i get message that is A problem caused the program to stop working correctly.windows will close the program and notify you if a solution is avilable

#include <stdio.h>
#include <stdlib.h>

int main()
{
  int arr[30],arr1[30];
  int n,i;
  int *p,*q;
  p=arr;
  q=arr1;
  printf("Enter the no. of elements of array:-\n");
  scanf("%d",&n);
  printf("Enter the array element of 1st array:-\n");
  for(i=0;i<n;i++)
  {
    scanf("%d",p+i);

  }
  for(i=0;i<n;i++)
  {
    q=(int*)*(p+i);
    q++;
  }
  printf("elements of array 1=");
  for(i=0;i<n;i++)
  {
    printf("%d , ",*(p+i));
  }
  printf("\nelements of array 2=");
  for(i=0;i<n;i++)
  {
    printf("%d , ",*(q+i));
  }
  for(i=0;i<n;i++)
  {
    printf("%d , ",arr1[i]);
  }
  return 0;
  }

Answer 1

Change

  for(i=0;i<n;i++)
  {
    q=(int*)*(p+i);
    q++;
  }

To

  for(i=0;i<n;i++)
  {
    q[i]=p[i];
  }

As of now you are treating int as int * and assigning it to pointer leading to undefined behaviour.

Also *(p+i) is same as p[i] and (p+i) is same as &p[i] . But latter ones are more readable.