Select customer with highest price of all his orders

Question

i want to list customer id with highest sum of price of his orders. Please see graph oí orders down.

Answer 1

SQL DEMO

 SELECT *
 FROM (
         SELECT "customerid", SUM("price")
         FROM  Orders
         GROUP BY "customerid"
         ORDER BY SUM("price") DESC
      ) T
WHERE ROWNUM <= 1      

Answer 2

You need to group by customer_id to get all prices of each customers. Then sum these prices filter it with max( sum(price))or get first row by descending order of sum(price).

--for Oracle

select * from (Select c.name,c.id,sum(o.price) from Customer c
inner join order o on o.customer_id=c.id
group by c.name,c.id
order by sum(o.price)desc
)where rownum =1

--For sql server and mysql

Select top 1 c.name,c.id,sum(o.price) from Customer c
inner join order o on o.customer_id=c.id
group by c.name,c.id
order by sum(o.price)desc