I have product and code entities, and I make ManyToMany relationship for them, so it gonna be Product_Code
so the Product_Code will have product_id and product_id
I really want to fetch data from the product by the code, but the result I want it I want detail from product values and code values also, I don't know how to do that on JPA
I was thinking to get the product code first, then find the id product on Product_Code table for that id , and then get data from it and find the id of code again on code entity, i am sure there is way to fetch data for this, but i don't know how, and i do like to get simple way to understand how it works
i am very new here
my entity product something like this
@Entity
@Table(name = "PRODUCT")
@Setter
@Getter
@DynamicUpdate
public class Product extends Base {
@ManyToMany(mappedBy = "products", fetch = FetchType.EAGER)
private Set<Code> codes;
@Column(name = "NAME", nullable = false)
private String Name;
@Column(name = "DESCRIPTION")
private String description;
public int hasCode() {
return Objects.hashCode(getId());
}
}
and here is my Code entity :
@Entity
@Table(name = "CODE")
@DynamicUpdate
@Setter
@Getter
public class Voucher extends Base {
@ManyToMany(cascade = { CascadeType.PERSIST, CascadeType.MERGE })
@JoinTable(name = "PRODUCT_CODE",
joinColumns = @JoinColumn(name = "CODE_ID"),
inverseJoinColumns = @JoinColumn(name = "PRODUCT_ID"))
private Set<Product> products;
@Column(name = "CODE", unique = true)
private String codeName;
@Column(name = "TYPE", nullable = false)
private String type;
private String descriptions;
public int hasCode() {
return Objects.hashCode(getId());
}
}
i really want to get the all of data when i try to find by code let say that i want to find a product with code like "A7", so i want to get from product entity and then i will get the detail code entity also with the product_id and code_id like that product
when i tried to Product findByCode(String code)
or Product findOneByCode(String code)
the result is the Base
entity which i extends not the Product entity , the Base
entity is reusable entity like generate id, token, createdAt, deletedAt, updatedAt
This can be achieved using Specification<Product>
on JpaSpecificationExecutor<Product>
-enabled repository.
ProductRepository
implements JpaSpecifiactionExecutor<Product>
then, somewhere in your @Service
with both VoucherRepository
and ProductRepository
injected do:
//implement a method in VoucherRepository findByName which returns Voucher instance.
Voucher code = voucherRepository.findByName("A7");
//then pass the instance to isMember function in ProductRepository
List<Product> products = productRepository.findAll((r, q, b) -> b.isMember(code, Product_.codes));
Comments
r, q, b
are method parameters for lambda-expression like implementation of Specification<Product>
overriding method toPredicate
. If your project restricts you using Java version 7 and below, you could implement this object using the following:
Specification<Product> spec = new Specification<Product>() {
@Override
public Predicate toPredicate(Root<Product> root, CriteriaQuery<?> criteriaQuery, CriteriaBuilder criteriaBuilder) {
return criteriaBuilder.isMember(code, root.get(Product_.codes));
}
};
Parameters
r
stands for root element Root<Product>
q
stands for criteria query CriteriaQuery<?>
b
stands for criteria builder CriteriaBuilder
Product_.*
is a static metamodel for your Product
entity. It could be either generated autmatically using JPA model generator or created manually using @Staticmetamodel
annotation.
By executing findAll(Specification<Product>)
you're making filtering-like select where your result List will contain only the products matching your criteria.
Edit:
Your Product
metamodel could look like (for now), but however, I recommend using metamodel generator.
@StaticMetamodel(Product.class)
public class Product_ {
public static volatile SetAttribute<Product, Code> codes;
}
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