Removing an element from a list based on a condition

Question

I need to remove an element (in this case a tuple) from one list based on a condition (if satisfied) in another list.

I have 2 lists (list of tuples).

List1 = [('a', 'b'), ('a', 'c'), ('a', 'd'), ('b', 'c'), ('b', 'd'), ('c', 'd')]


List2 = [(1, 2), (1, 3), (1, 2), (2, 3), (2, 2), (3, 2)]

List1 is basically computed from the following code.

import pandas as pd    
mapping = {'name': ['a', 'b', 'c', 'd'],'ID': [1,2,3,2]} 
df = pd.DataFrame(mapping)
comb = df['name'].to_list()
List1 = list(combinations(comb,2))

# mapping the elements of the list to an 'ID' from the dataframe and creating a list based on the following code
List2 = [(df['ID'].loc[df.name == x].item(), df['ID'].loc[df.name == y].item()) for (x, y) in List1]

Now I need to apply a condition here; looking at List2, I need to look at all tuples in List2 and see if there is any tuple with same 'ID's in it. For example, in List2 I see there is (2,2). So, I want to go back to List1 based on this remove the corresponding tuple which yielded this (2,2) pair.

Essentially my final revised list should be this:

RevisedList = [('a', 'b'), ('a', 'c'), ('a', 'd'), ('b', 'c'), ('c', 'd')]

('b','d') should be removed because they yield (2,2) same IDs in a set

Answer 1

List1 = [('a','b'), ('a','c'), ('a','d'), ('b','c'), ('b','d')]
List2 = [(1,2), (1,3), (1,2), (2,3), (2,2)]
new_List1 = [elem for index,elem in enumerate(List1) if List2[index][0]!=List2[index][1]]
// Result: [('a', 'b'), ('a', 'c'), ('a', 'd'), ('b', 'c')]

It is not entirely clear but is this what you are looking for? new_List1 only contains those indexes where at that index List2 has two different numbers in the tuple

Answer 2

我如何在R中做完全相同的事情（在我的情况下为vector）