Cannot convert value of type 'UIImage?' to expected argument type '[Any]'

Question

I am trying to send an image using a share button

I have an image in the UIViewcontroller called self.image

func share(_ sender: Any) {
    let imageToShare = self.image?
    let activityViewController = UIActivityViewController(activityItems: imageToShare, applicationActivities: nil)
    activityViewController.popoverPresentationController?.sourceView = self.view
    // present the view controller
    self.present(activityViewController, animated: true, completion: nil)
}

However I got the following error

Cannot convert value of type 'UIImage?' to expected argument type '[Any]'

Could it be that this has something to do with the optional value type of self.image? How do I make it non-optional while the function doesnt crash when someone click the button?

Answer 1

activityItems is expecting to get an Array. So you could make imageToShare non optional and send it as an Array (that contains only this image).

1. Make it non-optional using if let
2. Make an Array that contains this image using [imageToShare]

The complete solution would be:

if let imageToShare = self.image? {
            let activityViewController = UIActivityViewController(activityItems: [imageToShare], applicationActivities: nil)
            activityViewController.popoverPresentationController?.sourceView = self.view
            // present the view controller
            self.present(activityViewController, animated: true, completion: nil)
        }

Answer 2

If you're going to comprehend the error that says:

Cannot convert value of type 'UIImage?' to expected argument type '[Any]'

It literally says the type (optional or not!) is not the expected [Any] type. Since a UIImage can be Any , how about you try let imageToShare = [self.image] ?

In that case, you have [Any?] type. An Any? object in an Array . Now if it still complains about the optional thing (it probably will), which you already know, then unwrap that object safely in any way you want, to make it [Any] .