If the first character of my string contains any of the following letters, then I would like to change the first letter to Uppercase: (a,b,c,d,f,g,h,j,k,l,m,n,o,p,q,r,s,t,v,w,y,z) but not (e,i,u,x).
For example,
luke
would become Luke
egg
would stay the same as egg
dragon
would become Dragon
I am trying to acheive this with PHP, here's what I have so far:
<?php if($str("t","t"))
echo ucfirst($str);
else
echo "False";
?>
My code is simply wrong and it doesn't work and I would be really grateful for some help.
Without regex:
function ucfirstWithCond($str){
$exclude = array('e','i','u','x');
if(!in_array(substr($str, 0, 1), $exclude)){
return ucfirst($str);
}
return $str;
}
$test = "egg";
var_dump(ucfirstWithCond($test)); //egg
$test = "luke";
var_dump(ucfirstWithCond($test)); //Luke
Demo: http://sandbox.onlinephpfunctions.com/code/c87c6cbf8c616dd76fe69b8f081a1fbf61cf2148
You may use
$str = preg_replace_callback('~^(?![eiux])[a-z]~', function($m) {
return ucfirst($m[0]);
}, $str);
See the PHP demo
The ^(?![eiux])[az]
regex matches any lowercase ASCII char at the start of the string but e
, u
, i
and x
and the letter matched is turned to upper inside the callback function to preg_replace_callback
.
If you plan to process each word in a string you need to replace ^
with \\b
, or - to support hyphenated words - with \\b(?<!-)
or even with (?<!\\S)
(to require a space or start of string before the word).
If the first character could be other than a letter then check with an array range from az
that excludes e,i,u,x
:
if(in_array($str[0], array_diff(range('a','z'), ['e','i','u','x']))) {
$str[0] = ucfirst($str[0]);
}
Probably simpler to just check for the excluded characters:
if(!in_array($str[0], ['e','i','u','x'])) {
$str[0] = ucfirst($str[0]);
}
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