I have the following a model, I already try to order_by('cell_name')
but no same what I want. I want to order base on alphabet+number
field. Could you please have your suggestions on this??, any help will be appreciated.
#my model
class BuildingCell(models.Model):
....
cell_name = models.CharField(max_length=100, blank=True, null=True)
#my queryset
q1 = BuildingCell.objects.all().order_by('cell_name')
my result:
cell_name
10a
10b
10c
11a
11b
1a
1b
2a
2b
The result that I want:
1a
1b
2a
2b
10a
10b
11a
11b
You can sort the queryset manually:
q1 = BuildingCell.objects.all()
q1 = sorted(list(q1),key=lambda s:list(map(lambda x:int(x) if x.isdigit() else x,re.split(r'(\d+)',s.name)[1:])))
Assuming the data format outline is consistent with some number of digits followed by optional text you can parse data into 2 fields via regular expression and sort the resulting fields directly is the SQL statement.
with test_data (cell_name) as
( values ('10a')
, ('10b')
, ('10c')
, ('11a')
, ('11b')
, ('1a')
, ('1b')
, ('2a')
, ('2b')
, ('20') -- added
, ('20b') -- added
, ('ABC') -- Use only for no leading digits passibility
)
select cell_name
from test_data
order by
regexp_replace (cell_name, '^(\d+)(\D?.*)','\1')::integer
, regexp_replace (cell_name, '^(\d+)(\D?.*)','\2')
;
If it's possible that an entry does not have leading digits then expand the order by clause:
select cell_name
from test_name
order by
case when cell_name ~ '^(\d+)'
then regexp_replace (cell_name, '^(\d+)(\D?.*)','\1')::integer
else null::integer
end
, case when cell_name ~ '^(\d+)'
then regexp_replace (cell_name, '^(\d+)(\D?.*)','\2')
else cell_name
end ;
Converting to the appropriate Django/Python structure I'll have to leave to you as I don't know Django and little Python. Hope this helps.
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