Swift Array Filter Multidimensional Arrays

Question

I am trying to filter out arrays in an array condition

public struct SalesDO: Entity {
   public var ID: String = UUID().uuidString
   public var isDeleted: Bool = false
   public var salesItems = [SalesItemDO]()
}

public struct SalesItemDO: Entity {
   public var ID: String = UUID().uuidString
   public var isDeleted: Bool = false
   public var modifiers = [SalesItemModifierDO]()
}

public struct SalesItemModifierDO: Entity {
   public var ID: String = UUID().uuidString
   public var isDeleted: Bool = false
}

What i am trying to achieve is to filter out those SalesItem which is not deleted, together with the sales item modifiers inside not deleted as well

I try to use the Swift filter array function, but it is compiler error

let rawSales = self.service.getSales(object: SalesDO()) as? SalesDO
if var sales = rawSales {
   let filteredSalesItem = sales.salesItems.filter({$0.modifiers.filter({$0.isDeleted == false})})
}.filter({$0.isDeleted == false})

I also tried this code

// It becomes SalesItemModifierDO array
let filteredsales = sales.salesItems.flatMap({$0.modifiers.filter({$0.wbDeleted == false})}).filter({$0.wbDeleted == false})

For example

Item A is not deleted
   => Modifier 1
   => Modifier 2
   => Modifier 3 : Deleted
Item B is deleted 
   => Modifier 1
   => Modifier 2

I am trying to achieve a function that will only display Item A with only 2 modifiers, because the modifier 3 is already deleted.

Can someone guide on what I am missing? Any help given is highly appreciated. Thanks

Answer 1

You can filter the array to remove sale items that are deleted, then map the remaining ones to remove modifiers where the modifier is deleted.

let filteredSalesItem = sales.salesItems.filter({ !$0.isDeleted }).map { (item) -> SalesItemDO in
    var newItem = item // Need to make mutable interim item to change modifiers array
    newItem.modifiers = newItem.modifiers.filter({ !$0.isDeleted })
    return newItem
}