How to change the output of a dictionary format in to another

Question

My Dictionary is below

    d = {
   "interface": [
      {
         "device": "device1",
         "keyvalue": [
            {
               "id": 1,
               "ipv4-address": "192.168.1.1",
               },
            {
               "id": 2,
               "ipv4-address": "192.168.1.2",
                          }
         ],
         "physical": [
            {
               "id": "1",
               "interface": "0/0"

            },
            {
               "id": "2",
               "interface": "0/1"

            }

         ]
      }
   ]
}

My desired output

keys_ipv4_address_1 192.168.1.1 physical_interface_2 0/1

Here keys_ipv4_address_1 means interface['device']['keyvalue']['id' = 1]['ipv4-address']

physical_interface_2 means interface['device']['id' = 2]['interface']

My Code is below

for k,v in d.items():
    #print (v)
    for i in v:
        print (i['keyvalue'][0])
        print (i['physical'][1])

But I want the output in different format, how to achieve that. like physical_interface_2 means go to physical then interface then id 2

Answer 1

how about use recursive print to indicate which part is handling, such as

def recursive_print(a, output):
    if type(a) == str:
            print(output, a)
            return
    if type(a) == int:
            print(output, a)
            return
    if type(a) == list:
            for i in a:
                recursive_print(i, output)
            return
    if type(a) == dict:
            for key in a:
                recursive_print(a[key], output + ('_' if output else '') + key)
            return

Then call recursive_print(d, "") to print the path:

interface_device device1
interface_keyvalue_id 1
interface_keyvalue_ipv4-address 192.168.1.1
interface_keyvalue_id 2
interface_keyvalue_ipv4-address 192.168.1.2
interface_physical_id 1
interface_physical_interface 0/0
interface_physical_id 2
interface_physical_interface 0/1