My Dictionary is below.How to print the keys from another dictionary and value from deep nested dict in Python?
my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
filtered_map_dict = {'peers':'pe', 'remote_id':'id', 'remote_as':'as', 'uptime':'up'}
def seek_keys(d, key_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(k + ": " + list(v.keys())[0])
else:
print(k + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list)
seek_keys(my_nested_dict, filtered_list)
My Output:
peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002
Expected output:
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002
You need to print filter_list[k]
instead of simple k
. I have written an example code which provides the expected output.
Code:
def seek_keys(d, key_list, filter_list):
for k, v in d.items():
if k in key_list:
if isinstance(v, dict):
print(filter_list[k] + ": " + list(v.keys())[0])
else:
print(filter_list[k] + ": " + str(v))
if isinstance(v, dict):
seek_keys(v, key_list, filter_list)
seek_keys(my_nested_dict, filtered_list, filtered_map_dict)
Output:
>>> python3 test.py
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
as: 13002 # It should be "as" based on your filtered_map_dict. (Not "up" as you have written in your question.)
If you change your filtered_map_dict
to:
filtered_map_dict = {"peers": "pe", "remote_id": "id", "remote_as": "as", "uptime": "up"}
The output will be exactly what you want as you can see below.
>>> python3 test.py
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002
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