Finding regex patterns in strings in scala

Question

I'm trying to create a regex that matches strings that have /x+any number/ in them, where anything can be written before or after that.

I tried creating the following regex .*/x+\\\\d*/.*

An example of a string I'm trying to match is abc/x+10/tomorrow

Strings such as abc/x+/tomorrow should evaluate to false but is true.

Answer 1

You were very close, all you needed to do was escape all the / and + , and change \\d* (match between 0 and unlimited) to \\d+ (match between 1 and unlimited) in order to avoid matching abc/x+/tomorrow :

.*\/x\+\d+\/.*

Regex Demo

Answer 2

You could use for example findFirstIn which will return an Option.

You should match 1+ digits instead and the patten can be shortened to /x\\+\\d+/

val pattern = """/x\+\d+/""".r
pattern.findFirstIn("abc/x+10/tomorrow").isDefined
pattern.findFirstIn("abc/x+/tomorrow").isDefined

Output

res0: Boolean = true
res1: Boolean = false

Scala demo

Answer 3

Maybe,

^.*?x\+\d+.*$

might simply work with proper language-based escapings.

Demo

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If you wish to simplify/modify/explore the expression, it's been explained on the top right panel of regex101.com . If you'd like, you can also watch in this link , how it would match against some sample inputs.

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