There are three columns: Id
(char), Name
(char), and Score
(int).
First, we group by Id
and Name
and add Score
for each group. Let us call the added score total_score
.
Then, we group by Name
and take only the maximum of total_score
and its corresponding Id
and Name
. I've got everything else but I'm having a hard time figuring out how to get the Id
. The error I get is
Column 'Id' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
WITH Tmp AS
(SELECT Id,
Name,
SUM(Score) AS total_score
FROM Mytable
GROUP BY Id,
Name)
SELECT Name, -- Id,
MAX(total_score) AS max_score
FROM Tmp
GROUP BY Name
ORDER BY max_score DESC
WITH Tmp AS
(SELECT Id,
Name,
SUM(Score) AS total_score
FROM Mytable
GROUP BY Id,
Name)
SELECT Name, Id,
MAX(total_score) AS max_score
FROM Tmp
GROUP BY Name,id
ORDER BY max_score DESC
Try this. Hope this will help.
I am not sure about performance of below query but we can use window functions
to get maximum
value from data partition
.
SELECT
Id,
Name,
SUM(Score) AS total_score,
MAX(SUM(Score)) OVER(Partition by Name) AS max_score
FROM Mytable
GROUP BY Id, Name;
Tested -
declare @Mytable table (id int, name varchar(10), score int);
insert into @Mytable values
(1,'abc', 100),
(2,'abc', 200),
(3,'def', 300),
(3,'def', 400),
(4,'pqr', 500);
Output -
Id Name total_score max_score
1 abc 100 200
2 abc 200 200
3 def 700 700
4 pqr 500 500
WITH Tmp AS
(
SELECT Id,
Name,
SUM(Score) AS total_score
FROM Mytable
GROUP BY Id,
NAME
)
SELECT Name, Id,
MAX(total_score) AS max_score
FROM Tmp
GROUP BY Name,id
ORDER BY max_score DESC
Note:- If we are using aggregate function then we have to use other column as Group By....
In your case you are using SUM(Score) as aggregate function then we to use other column as Group by...
just add row_number()
partition by Name
to your query and get the 1st row (order by total_score
descending)
select *
from
(
-- your existing `total_score` query
SELECT Id, Name,
SUM(Score) AS total_score,
r = row_number() over (partition by Name order by SUM(Score) desc)
FROM Mytable
GROUP BY Id, Name
) d
where r = 1
You can select DENSE_RANK() with total_score
column and then select records with Rank = 1
. This will work for those also when there are multiple Name
which are having same total_score
.
WITH Tmp AS
(SELECT Id,
Name,
SUM(Score) AS total_score
FROM Mytable
GROUP BY Id, Name)
SELECT Id,
Name,
total_score AS max_score
FROM (SELECT Id,
Name,
total_score,
DENSE_RANK() OVER (PARTITION BY Name ORDER BY total_score DESC) AS Rank
FROM Tmp) AS Tmp2
WHERE Rank = 1
You can try this as well:
select id,name,max(total_score) over (partition by name) max_score from (
select id,name,sum(score) as total_score from YOURTABLE
group by id,name
) t
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