get a program that gets (three integers ) and display the value that is neither max nor min?
I tried to think of a way to get a number between max and min. My input is x,y,z which are (three integers ) how to get this number which is neither max nor min?
int x,y,z,max,min,between;
cout<<"enter 3 integer values \n";
cin>>x>>y>>z,between;
if (x>y&&x>z)
x=max;
else if (x<y&&x<z)
x=min;
else if(y>z&&y>x)
y=max;
else if (y<z&&y<x)
y=min;
else if(!max==between&& !min==between)
cout<<"not max or min is "<<between<<endl;
return 0;
}
will I know that this is not the right code but I know that the path is somewhere close.
get a number between max and min. input (three integers )
This is essentially the median of the three numbers.
A simple solution can be to take the elements in an array, sort them and then pick the middle element, like so,
int elements[3] = ... // contains x,y,z
std::sort(std::begin(elements), std::end(elements)); // sorts the elements
elements[1] // pick the middle element
I am assuming that all the numbers are distinct otherwise there is no number which is neither min nor max. For example, of the three numbers are 3, 3 and 3, 3 is both the min and max. There is no solution in such a case.
With this code you compare the first 2 variable to see witch of them is the max value and after that just compare with the other variable
if (x < y)
{
if (z < x)
{
return x;
}
else if(z < y) {
return z;
}
else {
return y;
}
}
else if (y < z)
{
if (z < x) {
return z;
}
else {
return y;
}
}
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