How do I keep the file name of an image when resizing it and saving it to another folder?

Question

I'm in an introductory neural networking class so mind my ignorance. Also my first SO post.

I'm trying to resize some very highly resolved images within a dataset into 80x80p grayscale images in a new dataset. However, when I do this, I'd like to keep the filenames of each new image the same as the original image. The only way I know how to resave images into a new file is through a str(count) which isn't what I want. The filenames are important in creating a.csv file for my dataset later.

The only SO post I can find that is related is this:

Use original file name to save image

But the code suggested there didn't work - wasn't sure if I was going about it the wrong way.

import os
from PIL import Image
import imghdr
count=0
path1 = "/Users/..."
path2 = "/Users/..."
listing = os.listdir(path1)  
for file in listing:
    type = imghdr.what((path1 + file))
    if type == "jpeg":   
        img = Image.open("/Users/..." +file).convert('LA')
        img_resized = img.resize((80,80))
        img_resized.save(path2 + str(count) + '.png')
        count +=1
    pass
pass

Answer 1

Reuse the original filename that you get from the for loop ie file and, split it into filename and extension using os.path.splitext() like below:

import os
from PIL import Image
import imghdr
count=0
path1 = "/Users/..."
path2 = "/Users/..."
listing = os.listdir(path1)  
for file in listing:
    type = imghdr.what((path1 + file))
    if type == "jpeg":   
        img = Image.open("/Users/..." +file).convert('LA')
        img_resized = img.resize((80,80))

        # splitting the original filename to remove extension
        img_filename = os.path.splitext(file)[0]
        img_resized.save(path2 + img_filename + '.png')
        count +=1
    pass

Another option, we can use python str 's built-in split method to split the original filename by . and discard the extension.

import os
from PIL import Image
import imghdr
count=0
path1 = "/Users/..."
path2 = "/Users/..."
listing = os.listdir(path1)  
for file in listing:
    type = imghdr.what((path1 + file))
    if type == "jpeg":   
        img = Image.open("/Users/..." +file).convert('LA')
        img_resized = img.resize((80,80))

        # splitting the original filename to remove extension
        img_filename = file.split(".")[0]
        img_resized.save(path2 + img_filename + '.png')
        count +=1
    pass

So, if an image has a name such as some_image.jpeg then, the img_filename will have a value some_image as we splitted by. and discarded .jpeg part of it.

NOTE: This option assumes the original_filename will not contain any . other than the extension.

Answer 2

I assume that image name is on path1. If so you can grap image name from there in this way:

x=path1.rsplit('/',1)[1]

We are splitting path1 on last slash and taking image name string via indexing.