I have a sql table that looks roughly like this:
+-----+------+-------+
| id | type | value |
+-----+------+-------+
| 1 | X | 20 |
| 2 | X | 30 |
| 3 | Y | 200 |
| 4 | Y | 500 |
| 5 | Y | 300 |
| 6 | Z | 5 |
+-----+------+-------+
For each type I want to retrieve the row with the maximum value. This is my expected result:
+-----+------+
| id | type |
+-----+------+
| 2 | X | <-- had value = 30
| 4 | Y | <-- had value = 500
| 6 | Z | <-- had value = 5
+-----+------+
In SQL, this can be expressed as follows (given that for each type there aren't two entries with the same value, which I can rule out):
select t1.id, t1.type from T t1
inner join (
select t2.type, max(t2.value) as max_value from T t2
group by t2.type
) on t1.type = t2.type
and t1.value = max_value
However I cannot find a way to express the same using QueryDSL (version 4). I tried this:
final JPQLQuery<Tuple> subquery = JPAExpressions
.from(q2)
.select(q2.type, q2.value.max())
.groupBy(q2.type);
final JPQLQuery<Tuple> query = JPAExpressions
.from(q1)
.select(q1.id, q1.type)
.from(q1)
.innerJoin(subquery) // <-- not allowed
.on(q1.type.eq(q2.type), q1.value.eq(q2.value.max()));
But innerJoin()
(and other join methods) only take an expression as parameter, not another query. The same goes for from()
.
The subquery can be put into the outer query's where
clause in the form of an exists
-expression:
final JPQLQuery<Tuple> subquery = JPAExpressions
.from(q2)
.select(q2.type, q2.value.max())
.groupBy(q2.type);
final JPQLQuery<Tuple> query = JPAExpressions
.from(q1)
.select(q1.id, q1.type)
.from(q1)
.where(subquery
.having(q1.type.eq(q2.type), q1.value.eq(q2.value.max()))
.exists());
Note that this query might be quite inefficient.
In order to get the top 1 element, you can use:
JPAExpressions.selectFrom(table)
.select(table.dateTimeColumn.max())
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