How to match the list item to content in the file

Question

I have a list1 = ['hi','world','of']

I have a.txt file

Hellohihowareyou
worldisfullofwonder

How to check whether hi , 'of' , and world exists in the file

pseudo code

import re
pattern = r''
for i in list1:
   #print (i)
   with open('file.txt','r'):
       content = f.read()
   test= re.search(pattern,content)
   print (test)

My Expected out ['hi','of'] , since there is no world in the file

Answer 1

You can also do it with in keywords, use regex if your pattern start to be more advanced.

Normal

list1 =  ['hi','world','of']
text = """ Hellohihowareyou
worldisfullofwonder"""
results = []
for element in list1:
    if element in text:
        results.append(element)
print(results)

List comprehension

results = [element for element in list1 if element in text]

print(results)

Answer 2

use this:

import re
file = 'file.txt'
content = ''
lst =  ['hi','world','of']

with open(file, 'r') as file_handler:
    content = file_handler.read()

result = re.findall('|'.join(lst), content)

Answer 3

import re
file = r'C:\Users\wind\Desktop\file.txt'
list1 = ['hi','of','wonderw']
pattern = r''
for i in list1:
    pattern = re.compile(i, re.IGNORECASE)
    with open(file,'r') as f:
        content = f.read()
        test= re.search(pattern,content)
        print (test)