I have a JPA query as below
public interface MyRepository extends JpaRepository<User, String> {
@Query(value = "select * from User where code like 'PER%'",
nativeQuery= true)
public List<User> findAllUsers(String param);
}
How do I replace the 'PER%' with?1
Thanks in advance.
public interface MyRepository extends JpaRepository<User, String> {
@Query(value = "select * from User where code like CONCAT(:param,'%')",
nativeQuery= true)
public List<User> findAllUsers(@Param("param") String param);
}
You can use the query parameter with index ?1
Query Creation and Spring Data JPA
@Query(value = "select * from User where code like ?1%",
nativeQuery= true)
public List<User> findAllUsers(String param);
OR passing parameters via name.
@Query(value = "select * from User where code like :param%",
nativeQuery= true)
public List<User> findAllUsers(@Param("param") String param);
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