Given a data structure ' posts ' like the following, is there a pythonesque/dict comprehension/efficient way of creating a dict with each of the ids as keys to the posts:
posts = [{"ids":[1,2],...}, {"ids":[5, 6, 7], ...},...]
want = {1: {"ids":[1,2],..}, 2:{"ids":[1,2],...}, 5: {"ids":[5,6,7],...}, 6:{"ids":[5,6,7],..}, ...}
# long way
d = {}
for post in posts:
for id in post['ids']:
d[id] = post
# one comprehension - dicts created and disposed on each loop
d = {}
for post in posts:
d.update({id: post for id in post['ids']})
I would hope the following would work - but the top level doesn't see the bottom level post
# ilegal: post not available
d = {id: post for id in post['ids'] for post in posts}
Any ideas? I see cases like this frequently and the loop seems ugly
You can use a dictionary comprehension:
posts = [{"ids":[1,2]}, {"ids":[5, 6, 7]}]
result = {i:b for b in posts for i in b['ids']}
Output:
{1: {'ids': [1, 2]}, 2: {'ids': [1, 2]}, 5: {'ids': [5, 6, 7]}, 6: {'ids': [5, 6, 7]}, 7: {'ids': [5, 6, 7]}}
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