Here is my code. I have to write a program that takes user input for a string and displays the frequency of each letter in that string. I get this as an error no matter what I do. What would be the proper way to get user input for this code. Any help would be much appreciated. Thanks::
error: array must be initialized with a brace-enclosed initializer
.
int main()
{
string input;
cin >> input;
char freq[100] = input;
int c = 0, count[26] = {0};
while ( freq[c] != '\0' )
{
if ( freq[c] >= 'a' && freq[c] <= 'z' )
count[freq[c]-'a']++;
c++;
}
for ( c = 0 ; c < 26 ; c++ )
{
if( freq[c] != 0 )
printf("%c occurs %d times in the entered string.\n",c+'a',count[c]);
}
}
Using std::string is better than old-style char,In fact.you should use those knowledge u r not familiar still.
But if u want to use char now,you can remove variable input.u can change first three lines in main() function to this:
char freq[100];
cin >> freq;
Hey I think I found the answer to my question:
#include <iostream>
#include <string.h>
using namespace std;
int main()
{
string input;
cout<<"Enter lowercase string: ";
cin>>input;
cout<<"Number of characters in string: "<<input.size()<<"\n";
std::string freq = input;
int c = 0, count[26] = {0};
for (std::string::size_type i = 0; i < input.size(); i++)
{
if ( freq[i] >= 'a' && freq[i] <= 'z' ){
count[freq[i]-'a']++;
}
c++;
}
for ( c = 0 ; c < 26 ; c++ )
{
if( count[c] != 0 )
printf("%c occurs %d times in the entered string.\n",c+'a',count[c]);
}
}
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