How to extract text at newline using regex pattern with python?
Question
My text is as follow:
"""
2.Consignee
VU TRINI GIA BAO SERVICE AND TRADING JOINY STOCK COMPANY
44/26 VO VAN DONG, STREET, O CHU DUA WARD
"""
What is the suitable regular expression pattern for me to extract out the value aft the title consignee?
Desired output:
VU TRINI GIA BAO SERVICE AND TRADING JOINY STOCK COMPANY
44/26 VO VAN DONG, STREET, O CHU DUA WARD
1 answers
solution1
0 2019-11-20 09:17:05
This might not be that generic, but I guess this gives what you expect:
print(re.sub("(?i)[. \n 0-9]*Consignee", "", re.sub("\n\n", "", text)))
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