I have a script in Python which gives a few files but I also need a log file. Usually I use this command in windows cmd:
py name.py > name.log
This script is part of a project and I need to run it from python. I tried this:
subprocess.call(["py","name.py",">","name.log"])
And it give me all the files that the script prepares but not the log file.
Use os.system
os.system("py name.py > name.log")
Or, you can just pass an open file handle for the stdout argument to subprocess.call
:
args = ['name.py']
cmd = ['py'] + args
with open('name.log', "w") as outfile:
subprocess.call(cmd, stdout=outfile)
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