regex for initials separated by commas?

Question

I'm trying to create a regex that can be used to verify if a string contains only initials, then followed by commas if there is more than one initial.

This is the best I've managed to do: "^([A-Za-z],[A-Za-z],[A-Za-z])$" by replacing all spaces with "" .

An example of an allowed string would be a, b, c, d, f, g

while one that wouldn't pass would be a, b, c, df, e

This only works for exactly 3 initials, so I was wondering how I could get it to work with more or less initials while also not letting any outliers through.

Edit: ^([A-Za-z],([A-Za-z],)*[A-Za-z])$" seems to work quite well, but how would I change this code to work for just 1 character (since I need the last character, which usually doesn't have a comma following it)

Answer 1

Try the following pattern:

^[A-Za-z](?:,\s+[A-Za-z])*$

This matches a single character/initial, then followed by zero or more commas followed by whitespace and another initial.

Demo

Answer 2

您可以使用此正则表达式来匹配首字母，它不查看逗号，只查看首字母并匹配多个找到的：

(?:[a-zA-Z][a-zA-Z])