I need this table with dates and values according the cost per day
day | cost_day
-------------------------
2019-11-17 | 25
2019-11-18 | 20
null | 10
I need that return cost 25 for day 2019-11-17 or cost 20 for day 2019-11-18 or cost 10 for others days like 2019-11-19 or 2019-11-20.
I tried this queries:
SELECT day, cost_day
FROM table WHERE day = COALESCE('2019-11-19', null::date)
This return correct for days 2019-11-17 and 2019-11-18, but return null for others days, like 2019-11-19.
SELECT day, cost_day
FROM table WHERE (day = '2019-11-19' OR day is null)
This return correct for other days that not included in the table but for days in the table like 2019-11-18, the query return two costs values. The value for the specific date and the value for null date.
I need this return just one value, because I will use this query like a subquery.
Can someone help me?
edit:
I need return the date found too. Example: If I found 2019-11-19, I need return day 2019-11-19 and cost_day 10.
How about this?
select cost_day
from t
where day is null or day = '2019-11-19'
order by (day is not null) desc;
EDIT:
select coalesce(day, '2019-11-19') cost_day
from t
where day is null or day = '2019-11-19'
order by (day is not null) desc;
You can use COALESCE()
with 2 queries for both cases:
SELECT '2019-11-19'::DATE "day",
COALESCE(
(SELECT cost_day FROM tablename WHERE day = '2019-11-19'::DATE),
(SELECT cost_day FROM tablename WHERE day IS NULL)
) cost_day
See the demo .
Results:
| day | cost_day |
| ---------- | -------- |
| 2019-11-19 | 10 |
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