Regex: get number after and before specific substring

Question

I'm new to regex and trying to get number after substring text and before first non-numeric value. I have:

const str = 'fasdfsdanvczx fdasvczx text 321,fasdgasdf'; str.toLowerCase().match(new RegExp('text (.*)[^0-9]'));

As a result I'm receiving: ["text 321,fasdgasdf", "321,fasdgasd"] but I want only 321 .

Thanks in an advance for any help.

Answer 1

You could match the digits only in the first capturing group and use word boundaries \\b to prevent text and the digits being part of a larger word.

Note to double escape the backslashes when using the RegExp constructor.

\btext (\d+)\b

Regex demo

 const str = 'fasdfsdanvczx fdasvczx text 321,fasdgasdf'; let res = str.toLowerCase().match(new RegExp('\\\\btext (\\\\d+)\\\\b')); console.log(res[1]);

Answer 2

Use lookbehind to find number after 'text ':

(?<=text )\d+

Or simply match parts and select second group:

(text )(\d+)

Answer 3

You may try splitting twice:

 var str = 'fasdfsdanvczx fdasvczx text 321,fasdgasdf'; var num = str.split(/text /)[1].split(/\\D/)[0]; console.log(num);

The first spiit leaves us with 321,fasdgasdf , and the second split discards everything from the comma onwards.