Python simple counting script

Question

Im trying to make a script that automatically counts and uses SendKeys to print out a range of numbers ,say 1 - 100. I can make the list but I dont know how to convert the numbers so SendKeys can type them out because so far I can only make it type keys.

from pynput.keyboard import Key, Controller
import time
keyboard = Controller()

count = 0

for i in range (1, 100) :
count = count + 1

time.sleep(5)
keyboard.press(i)
keyboard.release(i)

Answer 1

You're basically there. You don't need count , and you need to send the string of the key you want to press, and presumably a new line. As a shortcut you could use the Controller.type method.

from pynput.keyboard import Controller, Key
import time

keyboard = Controller()

def send_range(start, end, wait_time):
    for i in range(start, end+1):
        keyboard.type(str(i))
        keyboard.press(Key.enter)
        time.sleep(wait_time)

send_range(1, 100, 5)

Answer 2

import time
from pynput.keyboard import Controller
keyboard = Controller()

for i in range(0,101):
    keyboard.type(str(i)+'\n')
    time.sleep(5)

Remove '\\n' if u want to print in same line

Answer 3

If you want the easiest solution, you can use keyboard.type() to send the characters in the integer one after another.

from pynput.keyboard import Controller, Key
import time

keyboard = Controller()

for i in range(1,100):
    time.sleep(5)
    keyboard.type(i)

If you still want to use keyboard.press() and keyboard.release() , for example if you want to sleep between each key press rather than between each integer in the list, then you can convert your integer into a string and then iterate through the string, like so

from pynput.keyboard import Controller, Key
import time

keyboard = Controller()

for i in range(1,100):
    time.sleep(5)
    for j in str(i):
        keyboard.press(j)
        keyboard.release(j)