I need to do an n x n block in Python to display "*" for that block

Question

size = int(input("please enter an integer:"))
for row in range(size*1):
    print("*", end="")
print()
for column in range(1* size):
    print("*", end="")
print()

This is my code so far and I need it to print: for 2

**
**

and for 7

*******
*******
*******
*******
*******
*******
*******

I have gotten it to print

**
**

for 2 but for 7 I just get

*******
*******

Answer 1

The natural way to write this in many languages would use a nested loop. However, it is much easier in Python:

for i in range(size):
    print('*' * size)

Answer 2

You need to nest the for loops since you want the number of lines to be equal to the number of columns:

size = int(input("please enter an integer:"))
for row in range(size):
    for col in range(size):
        print('*', end="")
    print()

PS: You don't really have to mulitply by 1 in range .

Answer 3

You need to nest the two loops to achieve what you desire.

You can do it the following three lines with two tricks:

• You can generate a string of n '*' with the command "*" * size , therefore you need a single loop
• The for loop does not need an index, that is not used, so you can use _

The code looks like this:

size = int(input("please enter an integer:"))
for _ in range(size):
    print("*" * size)

Answer 4

Another way is to simply multiply strings - no loops:

size = int(input("please enter an integer:"))
print((('*'*size)+'\n')*size)

enjoy :D :D :D