main_df:
Name Age Id DOB
0 Tom 20 A4565 22-07-1993
1 nick 21 G4562 11-09-1996
2 krish AKL F4561 15-03-1997
3 636A 18 L5624 06-07-1995
4 mak 20 K5465 03-09-1997
5 nits 55 56541 45aBc
6 444 66 NIT 09031992
column_info_df:
Column_Name Column_Type
0 Name string
1 Age integer
2 Id string
3 DOB Date
how can i find data type error value from main df. For example from column info df we can see 'Name' is a string column, so in main df, 'Name' column should contain either string or alphanumeric other than that it's an error. I need to find those datatype error values in a separate df.
error output df:
Column_Name Current_Value Exp_Dtype Index_No.
0 Name 444 string 6
1 Age 444 int 2
2 Name 56441 string 6
0 DOB 4aBc Date 5
0 DOB 09031992 Date 6
i tried this:
for i,r in column_info_df.iterrows():
if r['Column_Type'] == 'string':
main_df[r['Column_Name']].loc[main_df[r['Column_Name']].str.match(r'[^a-z|A-Z]+')]
elif r['Column_Type'] == 'integer':
main_df[r['Column_Name']].loc[main_df[r['Column_Name']].str.match(r'[^0-9]+')]
elif r['Column_Type'] == 'Date':
i have stuck here,because this RE is not catching every errors. i don't know how to go further?
If I understood what you did, you created separate dataframes, which contains infos about your main one.
What I suggest would be instead to use the build-in methods offered by pandas to deal with dataframes.
For instance, if you have a dataframe main , then:
main.info()
will give you the type of object for each column. Note that a column can contain only one type, as it is a series, which is itself a ndarray.
So your column name cannot have anything else but strings that you would have missed. Instead, you can have NaN values. You can check for them with the help of
main.describe()
I hope that helped :-)
Here is one way of using df.eval()
,
Note : though this will check based on pattern and return non matching values. However, note that this cannot check valid types, example if date column has an entry which looks like a date but is an invalid date, this wouldnot identify that:
d={"string":".str.contains(r'[a-z|A-Z]')","integer":".str.contains('^[0-9]*$')",
"Date":".str.contains('\d\d-\d\d-\d\d\d\d')"}
m=df.eval([f"~{a}{b}"
for a,b in zip(column_info_df['Column_Name'],column_info_df['Column_Type'].map(d))]).T
final=(pd.DataFrame(np.where(m,df,np.nan),columns=df.columns)
.reset_index().melt('index',var_name='Column_Name',
value_name='Current_Value').dropna())
final['Expected_dtype']=(final['Column_Name']
.map(column_info_df.set_index('Column_Name')['Column_Type']))
print(final)
Output :
index Column_Name Current_Value Expected_dtype
6 6 Name 444 string
9 2 Age AKL integer
19 5 Id 56541 string
26 5 DOB 45aBc Date
27 6 DOB 09031992 Date
I agree there can be better regex
patterns for this job but the idea should be same.
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