Precision round off in Python

Question

If some Python code's output is in format like "x.xx" How to increase its precision ?

eg:

import math

tc= int(input())
for i in range(0,tc):
    x1,y1,x2,y2,v1,v2= map(int,input().split())

    #distance
    # d = abs(math.sqrt( abs((x1-x2)*(x1-x2)) + abs((y1-y2)*(y1-y2)) ))

    #d1
    d1 = abs(math.sqrt( abs((x1-x1)*(x1-x2)) + abs((y1-0)*(y1-0)) ))


    #d2
    d2 = abs(math.sqrt( abs((x1-x2)*(x1-x2)) + abs((0-y2)*(0-y2)) ))


    niche = d1/v1
    upar = d2/v2

    roundoff = float("{:.5f}".format(niche+upar))
    print(roundoff)

its output is 5.5 make its output as 5.50000.

Answer 1

print(roundoff) is pretty printing the float value. So you just need to remove the float conversion:

roundoffstr = "{:.5f}".format(niche+upar)
print(roundoffstr)