how to select date range by specified year-month in sql

Question

I have a table in mysql server database called mytbl . There is a date column prod_date that contains all the date in year 2019 in the format 2019-xx-xx .

I need to extract all rows that from Jan 2019 to May 2019 . My following code is not returning anything.

SELECT * 
FROM mytbl
WHERE prod_date BETWEEN CONCAT('2019', '-', '01') AND CONCAT('2019', '-', '05')

Can someone tell what I did wrong? How I can select the date from by year and month only?

Thanks a lot in advance.

Answer 1

这应该只是给你结果。

SELECT * from mytbl WHERE Year(prod_date) = 2019 and Month(prod_date) BETWEEN 1 and 5

Answer 2

You don't need to use concat() just do :

where prod_date >= '2019-01-01' and prod_date <= '2019-05-31'

This assumes prod_date has YYYY-MM-DD format.

Answer 3

You can select the rows between two dates like if your date format is 'YYYY-MM-DD'. If you have the other formats, you can change the formats and query.

SELECT `mytbl`.* FROM `mytbl` where `prod_date` BETWEEN '2019-01-01' AND '2019-05-31'

Answer 4

Just use an inequality:

SELECT * 
FROM mytbl
WHERE prod_date >= '2019-01-01' AND prod_date < '2019-06-01';

For a small explanation, the right condition restricts to dates strictly less than midnight of June 1, 2019, which includes all of May of the same year. Note that writing the WHERE clause this was is sargable , meaning that an index using the prod_date might be usable.

Answer 5

不是一个好的解决方案，而是对您的查询进行编辑。

SELECT * FROM mytbl WHERE prod_date BETWEEN CONCAT('2019','-','01','-','01') AND CONCAT('2019','-','06','-','01')

Answer 6

假设您使用的是 SQL SERVER，您可以使用：SELECT * FROM mytbl WHERE datepart(year,prod_date)='2019' and datepart(month,prod_date) in (01,02,03,04,05)