Sum of all numbers in a sequence for loop

Question

I'm new to python and I'm doing exercises regarding loops. I'm wondering how can I get sum of all the numbers in a for loop sequence?

for num in (12, 1, 3, 33, -2, -5, 7, 0, 22, 4): # this is the sequence and it shouldn't be altered
    if num == 0: # once it encounters 0 it should stop
        print("Done")
        break
        continue
    else:
            print(sum(num)) # otherwise print the sum of all numbers

I've sorted it this way, but it's a different exercise.

def process(numbers):
    for num in numbers:
        if num == 0:
            break
    else:
        x = sum(numbers)
        print(x)
    return 'Done'

process(( 12, 4, 3, 33, -2, -5, 7, 0, 22, 4 ))

I would like to see a solution for the first case without defining a function with it's parameter of sequence, just as it is in the first code block. Thank you in advance. print(sum(num)) doesn't work since object is not iterable.

Answer 1

If we know for sure that 0 exists this can be done in a fairly cheeky way (at the cost of having to iterate the list twice and the creation of a new list):

sum(numbers[:numbers.index(0)]) 

But the proper way to do it is with an explicit loop like you tried, just with the correct logic:

def process(numbers):
    s = 0
    for num in numbers:
        if num == 0:
            break
        s += num
    print(s)
    return 'Done'