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How to know if a string includes at least one element of array in Javascript

let theString = 'include all the information someone would need to answer your question'

let theString2 = 'include some the information someone would need to answer your question'

let theString3 = 'the information someone would need to answer your question'

let theArray = ['all', 'some', 'x', 'y', 'etc' ]

theString true because there is 'all', theString2 true because there is 'some', theString3 false because there is no 'all' or 'some'

const theStringIsGood = theString.split(' ').some(word => theArray.includes(word))

此代码将句子拆分为每个单词,并检查是否有任何单词与匹配集 theArray 匹配。

You could use the string.includes() method. But in this case theString3 would still return true because some is in something. You could create a helper function to see if a string is within an array instead:

function findString(arr, str) {
    let flag = false;
    let strArr = str.split(' ');
    arr.forEach(function(s) {
        strArr.forEach(function(s2) {
            if(s === s2) {
                flag = true;
            }
        });
    });
    return flag;
};

Now you can pass the array and one of the strings to the function and test it.

you can do this with regex simply :

function ArrayInText(str, words) {
    let regex = new RegExp("\\b(" + words.join('|') + ")\\b", "g");
    return regex.test(str);
}

in regex \\b is words boundary

and notice, if you split all string yourself and check one by one, a lot of memory use, because it is a greedy solution. I offer that using javascript native functions.

snippet :

 let theString = 'include all the information someone would need to answer your question' let theString2 = 'include some the information someone would need to answer your question' let theString3 = 'the information someone would need to answer your question' let theArray = ['all', 'some', 'x', 'y', 'etc'] function ArrayInText(str, words) { let regex = new RegExp("\\\\b(" + words.join('|') + ")\\\\b", "g"); return regex.test(str); } console.log(ArrayInText(theString, theArray)); console.log(ArrayInText(theString2, theArray)); console.log(ArrayInText(theString3, theArray));

good luck :)

1) isIncludeWord -- look for exact word match using split and includes method.
2) isInclude -- look for match contain using some and includes .

 let theString = "include all the information someone would need to answer your question"; let theString2 = "include some the information someone would need to answer your question"; let theString3 = "the information someone would need to answer your question"; let theArray = ["all", "some", "x", "y", "etc"]; const isIncludeWord = (str, arr) => str.split(" ").reduce((include, word) => include || arr.includes(word), false); const isInclude = (str, arr) => arr.some(item => str.includes(item)); console.log(isIncludeWord(theString, theArray)); console.log(isIncludeWord(theString2, theArray)); console.log(isIncludeWord(theString3, theArray)); console.log(isInclude(theString, theArray)); console.log(isInclude(theString2, theArray)); console.log(isInclude(theString3, theArray));

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