char array[]= {1,2,3,4,5,6,7,8,9,1,2,3,6,7};
printf("%c\n", array[5]);
This returns " ". Nothing but when I change the char to int it prints "5". I tot char can accept numbers from -128 to 127?
int array[]= {1,2,3,4,5,6,7,8,9,1,2,3,6,7};
printf("%i\n", array[5]);
When you print the char
, C assumes the value stored is supposed to represent ASCII encoded text. Accessing array[5]
yields the value 6
, which corresponds the ASCII value ACK
. This character is not printable, which is why you see no output.
The character 6
is represented by the ASCII value 54
. To produce this value, use the char
literal '6'
.
For example, try initializing your array as:
char array[]= {'1','2','3','4','5','6','7','8','9','1','2','3','6','7'};
This will result in the behavior you expect.
Alternatively, you can print the character as a formatted integer by using the flag %i
in place of %c
in your first snippet.
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