String.replace(x,x,count => 1) in Python

Question

I am new to python and learning it. In my project code I saw in the replace function the count is given in this format. When I run in Python editor it gives this error.

"Bharath..Bharath..Bharath".replace("..", ".", count => 1)

SyntaxError: invalid syntax

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<string>", line 1, in <module>
  File "/usr/lib/python3.7/py_compile.py", line 147, in compile
    raise py_exc
py_compile.PyCompileError:   File "./prog.py", line 1

    x="Bharath..Bharath..Bharath".replace("..", ".", count => 1)

                                                            ^
SyntaxError: invalid syntax

Can anyone tell me what this count => 1 means i understand that the last parameter is the no of occurrences to replace.

Thanks

Answer 1

In Python this can be done very easily String.replace(StringToReplace, ReplaceWith, Count)

For your example

x="Bharath..Bharath..Bharath".replace("..", ".", 1) should work. Keywords like "count" dont work here.

So you were close to the solution. :)

Answer 2

Replace 方法不接受关键字参数，因此只需使用以下代码更新您的代码。

"Bharath..Bharath..Bharath".replace("..", ".", 1)